jax.numpy.floor_divide

jax.numpy.floor_divide(x1, x2, /)

Return the largest integer smaller or equal to the division of the inputs.

LAX-backend implementation of numpy.floor_divide().

Original docstring below.

It is equivalent to the Python // operator and pairs with the Python % (remainder), function so that a = a % b + b * (a // b) up to roundoff.

Parameters:

• x1 (array_like) – Numerator.

• x2 (array_like) – Denominator. If x1.shape != x2.shape, they must be broadcastable to a common shape (which becomes the shape of the output).

Returns:

y – y = floor(x1/x2) This is a scalar if both x1 and x2 are scalars.

Return type:

ndarray