jax.numpy.equal(x1, x2)

Return (x1 == x2) element-wise.

LAX-backend implementation of equal(). Original docstring below.

equal(x1, x2, /, out=None, *, where=True, casting=’same_kind’, order=’K’, dtype=None, subok=True[, signature, extobj])


x2 (x1,) – Input arrays. If x1.shape != x2.shape, they must be broadcastable to a common shape (which becomes the shape of the output).


out – Output array, element-wise comparison of x1 and x2. Typically of type bool, unless dtype=object is passed. This is a scalar if both x1 and x2 are scalars.

Return type

ndarray or scalar


>>> np.equal([0, 1, 3], np.arange(3))
array([ True,  True, False])

What is compared are values, not types. So an int (1) and an array of length one can evaluate as True:

>>> np.equal(1, np.ones(1))
array([ True])